- An Example of 1D array in JAVA :
import java.io.*;
class array
{
public static void main(String args[]) throws IOException
{
int[] anArray;
// allocates memory for 10 integers
anArray = new int[10];
// initialize first element
anArray[0] = 100;
// initialize second element
anArray[1] = 200;
// and so forth
anArray[2] = 300;
anArray[3] = 400;
anArray[4] = 500;
anArray[5] = 600;
anArray[6] = 700;
anArray[7] = 800;
anArray[8] = 900;
anArray[9] = 1000;
System.out.println("Element at index 0: "
+ anArray[0]);
System.out.println("Element at index 1: "
+ anArray[1]);
System.out.println("Element at index 2: "
+ anArray[2]);
System.out.println("Element at index 3: "
+ anArray[3]);
System.out.println("Element at index 4: "
+ anArray[4]);
System.out.println("Element at index 5: "
+ anArray[5]);
System.out.println("Element at index 6: "
+ anArray[6]);
System.out.println("Element at index 7: "
+ anArray[7]);
System.out.println("Element at index 8: "
+ anArray[8]);
System.out.println("Element at index 9: "
+ anArray[9]);
}
}
- Program to find the maximum no in an array using java:
import java.io.*;
class max
{
public static void main(String args[]) throws IOException
{
int x[]=new int[5];
int max=0;
InputStreamReader is= new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(is);
for(int i=0;i<5;i++)
{
System.out.println("Enter numbers");
x[i]=Integer.parseInt(br.readLine());
max=x[0];
for(int i=0;i<5;i++)
{
if(max<x[i])
{
max=x[i];
}
}
System.out.println("Maximum no is .. "+max);
}
}
}
Sample Output :
Enter Numbers: 1 2 3 4 5
Maximum no is .. 5
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